### A Radical Prompt

__Blogging Prompt__Here's the Blogging Prompt we discussed in class today:

Without using a calculator find the value of:

sq.rt.(3 ^{2}+ 4^{2}+ 12^{2})sq.rt.(7 + sq.rt.(4))

Your challenge, should you choose to accept it, is to create tworadicalproblems of your own similar to those above. This challenge is open to all takers! However, once a solution is posted you CANNOT use the same solution as your own -- you've got to come up with a new one. In other words, the longer you wait to tackle this, the harder it's going to get.

Write your answers in the comments to this post. You can also use cube roots (cube rt.), fourth roots (4th.rt.) and higher if you wish. Feel free to mix them up too! (i.e. square roots and cube roots, or square roots and fourth roots, etc.) A successful reply to this prompt includes TWO answers; one similar to each of the problems posted. If you have a successful reply you do not need to write a reflective pre-test blog post.

*Have Fun!*
## 39 Comments:

sq. rt.(4^2+9^2+7^2)

sq rt.(6+sq. rt.(14))

for the second one is

sq. rt.(6+sq. rt.(14))

sorry forget the dot

Sorry Jan, try again.

The first one equals sq.rt.(146), which IS NOT a whole number.

In the second one sq.rt.(14) IS NOT a whole number.

sq.rt.(5^2+19^2+13^2)

sq.rt.(9+sq.rt.(324))

This comment has been removed by a blog administrator.

a) sq. rt. (5² + 12²0

= 25 + 144

= 169

sq. rt. = 13.

b) sq. rt. (13 + sq. rt. 9)

= 13 + 3

= 16

sq. rt. = 4

sq.rt. (4^2+12^2+3^2)

if we made a blogging prompt already, do we still have to do this?

sq.rt (4 + sq.rt. 25) ?

cause this is hard lol

sq. rt.(20^2+12^2+16^2)

sq. rt.(6+ sq(9))

So far NO ONE has earned that blog prompt mark.

Thang - you heard me in class, right?

In order to get that mark you need to have TWO problems, one modeled after each of the ones I presented, that can be solved as whole numbers. SOme of you have one correct but not the other.

If you have already posted your pre-test reflective blog you already have your blogging mark. (i.e. Janet)

A.

--------- ?

√4^2+12^2+3^2

B.

----- ?

√2+√49

sq. rt.(12^2+4^2+3^2)

sq. rt.(6+sq. rt.(9))

sq.rt.(9^2+4^2+5^2) for the first one

second one sq.rt.(8+sq.rt(64)

did i get it mr.k

a) cube.root.( 10sq.+ 3sq.+ 4sq.)

b) sq.rt.(95 + (sq.rt.9)+(sq.rt.4))

I'll change my display, this is Jordan.

NOOOOOOOOOOOOOOOOOOOOOOOOOOOOO! I forgot about this right after I left class! Now it's too late :(

=_=

sq rt. (12^2+9^2+8^2)

=sq rt. (144+81+64)

=sq rt. (289)

=14

sq rt. (28+ sq rt.(64))

=sq rt. (28+8)

=sq rt. (36)

=6

tell me if i got the mark mr. k! i dont want to do that reflective thingy, not after i have all this math to do. haha, yeah.

1.

Sq.Rt(6^2+3^2+2^2)

= Sq.Rt(36+9+4)

= Sq.Rt(49)

= 7

2.

Sq.Rt(6+Sq.Rt(9))

= Sq.Rt(6+3)

= Sq.Rt(9)

= 3

sq. rt(2^2+ 6^2+ 3^2)

second one is

sq. rt(21+ sq rt.(100))

ill change my first answer to:

cube root (2^3+ 3^3+ 4^3)

sq. rt (10 + 3 + 7^2 + 8 + 3^2 + 2)

1.) SQ.RT.(2^2 + 6^2 + 9^2)

= SQ.RT.(4 + 36 + 81)

= SQ.RT.(121)

= 11

2.) SQ.RT.(4 + Sq.Rt.(144))

= SQ.RT.(4 + 12)

= SQ.RT. (16)

= 4

PLEASE BE RIGHT!!!! QUICK QUICK QUICK RACE!

SAMUS you got it but your solution to the first one is incorrect, please repost and fix it.

Jojo you also have both right but you second problem was presented earlier by someone else. Repost. Keep your first one; create a new second radical.

EVERYONE READ THIS:

This: sq. rt.(12^2 + 4^2 + 3^2)

and this: sq. rt.(12^2 + 3^2 + 4^2)

and this: sq. rt.(4^2 + 12^2 + 3^2)

etc.

ARE ALL THE SAME AS THE ORIGINAL RADICAL I GAVE YOU.

tim-math-y, yours is perfect! You got the mark.

Again, EVERYONE, please take note:

When you repost your problems repost them BOTH -- don't make me hunt through the earlier posts to verify your work.

You guys are all doing some really good thinking! Don't give up; you CAN do this!!!!!

wat did i do wrong?

nevermind

lol this is hilarious xD

Mr K did i get mine right ??

b) sq. rt. (36+ sq. rt. 9)

= 6 + 3

= 9

sq. rt. = 3

Mr K, hope you are happy with my questions.

Yes I did get my answer wrong. I was hopeing that Mr. K wouldn't notice it. What it was supposed to be was,

sq rt. (12^2+9^2+8^2)

=sq rt. (144+81+64)

=sq rt. (289)

=

17And that fixxes the first math problem I did incorrectly. But I did do my second one right =)

The people who have got their blog mark for correctly replying to this prompt are:

tim-math-y

SAMUS

The rest of you either have both or one of your problems incorrect. The errors are either;

(a) mathematically incorrect or

(b) you didn't create both problems

SIMILARto the ones I posted.Don't give up! Keep trying. You

CANdo this!! ;-)b)

sq. rt. (36+ sq. rt. 9)

= 6 + 3

= 9

And the sq. rt. of 9 is three.

Maybe that's it. I hope so.

PS. Everyone click on my name, lol.

a)

sq. rt. (5² + 12² )

= 25 + 144

= 169

sq. rt. = 13.

Maybe that's it. I forget the other bracket.

or

sq. rt. (5² + 12² + 3³)

= 25 + 144 + 27

= 196

sq. rt. = 14.

Hee hee... By jolly, I think I got it.

Not yet Thang -- use either all squares or all cubes. You can try to find a cube root of a sum of three squares if you like, or something

similarto that.Your other problem and solution is incorrect.

Please go back and READ ALL MY EARLIER COMMENTS on this post.

Redoing the second one...

Sq.Rt(88 + Sq.Rt(144))

Sq.Rt(88 + 12)

Sq.Rt(100)

=10

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