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Sunday, November 06, 2005

Test Is Coming Up!

Hi everyone!

Another weekend has come through again, and school starts again tomorrow. AND we have a test coming up this week, I don't know when, but I guess there's nothing wrong in preparing, eh? Oh, and I just remembered to blog before the test, so I decided to blog now before I forget.

Anyway, this new unit, about radicals, was quite enjoyable. It was quite hard to understand it at first, I mixed up on some parts like when we broke down radicals like √12 breaks down to √4 times √3, and simplifying that, we have a mixed radical, which is 2√3. And oh, mixed radicals are radicals which are composed of a whole number and a radical. Example: refer to the simplified answer of √12. Another thing we learned in radicals is how to write a radical to an exponential form, and vice versa. √12 converted to exponential form is 12^1/2. 8^1/2 written in radical form is √8.

Another thing is we learned how to add, subtract, multiply and divide radicals. One time, we encountered a problem like this: 2√2 + 4√2 + 6√2 is similar the problem 2x + 4x +6x. So, combining those terms, you get 12√2. Like I said, it is similar to the problem 2x + 4x + 6x. But what if we don't have similar terms, like 2√2 + 4√2 - 6√3? Well then, it similar to the equation 2x + 4x -6y. We don't combine unlike terms, and such. What about the problem √8 + √32 + √72? The first step when we encounter this problem is to simplify the radicals first. So √8 simplifies to 2√2, √32 to 4√2, and √72 to 6√2. 12√2 is the answer. Did I just write the answer somewhere here?

In multiplying, we just simply distribute the radical to each term e.g √2(√9+√2) = 9√2 + 2. Division of radicals is also just the same as 3x^2/3x e.g. 6√2/3√2, simplifies to 2.

Well, I guess that summarizes what we learned in radicals. I've exhausted all my knowledge in this blog.. and I wish good luck to everyone in the test.


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