Hello every body

The scribe for today is me and I hope, i explain it clear

The first thing that Mr. Tram ( the subtitute teacher) did was finish answering question 19, 18 from the exercise #13, and question 4, 5, 8, 9, 10, 20 from the exercise #14

After we study the “CONSTRUCTING LINEAR EQUATION.”

"in order to drew a straight line, we need 2 pints andThere for , we should be able to construct linear equation from any 2 given pints."

RECALL: the slope-Y intercept form of a linear equation is:

Y=Mx+b

M is the slope, b is the y line

Were: M=y2-y1/x2-x1

after the short lesson we finished the class by doing 3 Exs.

Ex #1: Construct a linear equation of a line that pass through ( 2 , 1 ) and ( 4 , 6 )

M=6-1/4-2=5/2

y=5/2 x+b

1=5/2(2)+b

1=5+b

b=-4

y=5/2x-4 is the desired equation

Ex #2:Construct a linear equation of a line that pass through ( 4 , -1 ) and ( 8 , -2 ) find y=y=mx+b

m=(-2)-(-1)/8-4=

(-2)+1/4=

-1/4

Y=-1/4x+b

-1=-1/4(4)+b

-1=-1+b

b=0 y=-1/4x+0 or y=-1/4x

Ex#3: find y=mx+b, if the slope is -2 and the point is (4 , 2 )

2=-2(4)+b

2=-8+b

8+2=b

10=b .'. y=-2x+10

And the last exercise was:

construct y=mx+5 for a line that is parallel to 2x+3y+6=0, having the same y-int.as y=3/4x+2

and we have to find the answer ourselves :(

By the way, i'm sure everyone is looking forward to see Mr. k tomorrow.

and we will also miss Mr. Tram. ^_^

And scribe for tomorrow is<<<

(if not appropriate, then Jan Hong)

See you!

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