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Wednesday, October 05, 2005

Hello every body
The scribe for today is me and I hope, i explain it clear
The first thing that Mr. Tram ( the subtitute teacher) did was finish answering question 19, 18 from the exercise #13, and question 4, 5, 8, 9, 10, 20 from the exercise #14
After we study the “CONSTRUCTING LINEAR EQUATION.”
"in order to drew a straight line, we need 2 pints andThere for , we should be able to construct linear equation from any 2 given pints."
RECALL: the slope-Y intercept form of a linear equation is:
Y=Mx+b
M is the slope, b is the y line

Were: M=y2-y1/x2-x1
after the short lesson we finished the class by doing 3 Exs.
Ex #1: Construct a linear equation of a line that pass through ( 2 , 1 ) and ( 4 , 6 )
M=6-1/4-2=5/2
y=5/2 x+b
1=5/2(2)+b
1=5+b
b=-4
y=5/2x-4 is the desired equation
Ex #2:Construct a linear equation of a line that pass through ( 4 , -1 ) and ( 8 , -2 ) find y=y=mx+b
m=(-2)-(-1)/8-4=
(-2)+1/4=
-1/4
Y=-1/4x+b
-1=-1/4(4)+b
-1=-1+b
b=0 y=-1/4x+0 or y=-1/4x
Ex#3: find y=mx+b, if the slope is -2 and the point is (4 , 2 )
2=-2(4)+b
2=-8+b
8+2=b
10=b .'. y=-2x+10

And the last exercise was:
construct y=mx+5 for a line that is parallel to 2x+3y+6=0, having the same y-int.as y=3/4x+2
and we have to find the answer ourselves :(

By the way, i'm sure everyone is looking forward to see Mr. k tomorrow.
and we will also miss Mr. Tram. ^_^

And scribe for tomorrow is<<<>>>> :D
(if not appropriate, then Jan Hong)
See you!

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